What is the vertices 25x^2-9y^2-225=0 ?

The vertices 25x^2-9y^2-225=0 is (3,0),(-3,0)

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vertices 25x^2-9y^2-225=0

vertices

25 x^{2} - 9 y^{2} - 225 = 0

(3, 0), (- 3, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

25 x^{2} - 9 y^{2} - 225 = 0 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 5

(0 + 3, 0), (0 - 3, 0)

Refine

(3, 0), (- 3, 0)

5 x^{2} - 4 y^{2} - 40 x + 24 y + 24 = 0

x^{2} - y^{2} - 4 x - 6 y - 14 = 0

x^{2} - 16 y^{2} = 64

\frac{x ^{2}}{4} - \frac{y ^{2}}{81} = 1

\frac{( y - 1 ) ^{2}}{9} - \frac{( x + 3 ) ^{2}}{16} = 1

What is the vertices 25x^2-9y^2-225=0 ?
The vertices 25x^2-9y^2-225=0 is (3,0),(-3,0)