What is the vertices y^2-x^2= 4/25 ?

The vertices y^2-x^2= 4/25 is (0, 2/5),(0,-2/5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices y^2-x^2= 4/25

vertices

y^{2} - x^{2} = \frac{4}{25}

(0, \frac{2}{5}), (0, - \frac{2}{5})

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

y^{2} - x^{2} = \frac{4}{25} :

Up-down Hyperbola with

(h, k) = (0, 0), a = \frac{2}{5}, b = \frac{2}{5}

(0, 0 + \frac{2}{5}), (0, 0 - \frac{2}{5})

Refine

(0, \frac{2}{5}), (0, - \frac{2}{5})

- 16 x^{2} + 25 y^{2} - 64 x - 150 y - 239 = 0

- 9 x^{2} + 16 y^{2} - 90 x + 128 y - 113 = 0

2 y^{2} - 3 x^{2} - 4 y + 12 x + 8 = 0

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{18} = 1

\frac{x ^{2}}{1} - \frac{y ^{2}}{35} = 1

What is the vertices y^2-x^2= 4/25 ?
The vertices y^2-x^2= 4/25 is (0, 2/5),(0,-2/5)