What is the vertices-16x^2+25y^2-64x-150y-239=0 ?

The vertices-16x^2+25y^2-64x-150y-239=0 is (-2,7),(-2,-1)

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vertices-16x^2+25y^2-64x-150y-239=0

vertices

- 16 x^{2} + 25 y^{2} - 64 x - 150 y - 239 = 0

(- 2, 7), (- 2, - 1)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

- 16 x^{2} + 25 y^{2} - 64 x - 150 y - 239 = 0 :

Up-down Hyperbola with

(h, k) = (- 2, 3), a = 4, b = 5

(- 2, 3 + 4), (- 2, 3 - 4)

Refine

(- 2, 7), (- 2, - 1)

- 9 x^{2} + 16 y^{2} - 90 x + 128 y - 113 = 0

2 y^{2} - 3 x^{2} - 4 y + 12 x + 8 = 0

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{18} = 1

\frac{x ^{2}}{1} - \frac{y ^{2}}{35} = 1

\frac{( x + 6 ) ^{2}}{9} = \frac{( y - 2 ) ^{2}}{16} + 1

What is the vertices-16x^2+25y^2-64x-150y-239=0 ?
The vertices-16x^2+25y^2-64x-150y-239=0 is (-2,7),(-2,-1)