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Popular >

vertices-4x^2+y^2=4

Solution

vertices

- 4 x^{2} + y^{2} = 4

Solution

(0, 2), (0, - 2)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

- 4 x^{2} + y^{2} = 4 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 1

(0, 0 + 2), (0, 0 - 2)

Refine

(0, 2), (0, - 2)

Popular Examples

vertices 4x^2-y^2-16x-6y-9=0 vertices

4 x^{2} - y^{2} - 16 x - 6 y - 9 = 0

vertices 4x^2-9y^2=144 vertices

4 x^{2} - 9 y^{2} = 144

vertices f(x)f(x)=3(x+6)(x+3)vertices

f (x) f (x) = 3 (x + 6) (x + 3)

vertices 4x^2-9y^2-16x+18y-7=0 vertices

4 x^{2} - 9 y^{2} - 16 x + 18 y - 7 = 0

vertices (x^2)/7-(y^2)/6 =1 vertices

\frac{x ^{2}}{7} - \frac{y ^{2}}{6} = 1

Frequently Asked Questions (FAQ)

What is the vertices-4x^2+y^2=4 ?
The vertices-4x^2+y^2=4 is (0,2),(0,-2)