What is the vertices 4x^2-9y^2=144 ?

The vertices 4x^2-9y^2=144 is (6,0),(-6,0)

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vertices 4x^2-9y^2=144

vertices

4 x^{2} - 9 y^{2} = 144

(6, 0), (- 6, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

4 x^{2} - 9 y^{2} = 144 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 4

(0 + 6, 0), (0 - 6, 0)

Refine

(6, 0), (- 6, 0)

f (x) f (x) = 3 (x + 6) (x + 3)

4 x^{2} - 9 y^{2} - 16 x + 18 y - 7 = 0

\frac{x ^{2}}{7} - \frac{y ^{2}}{6} = 1

9 x^{2} - 16 y^{2} + 54 x - 16 y = - 113

(\frac{y - 4}{4})^{2} - (\frac{x - 6}{4})^{2} = 1