What is the vertices y^2-x^2= 1/36 ?

The vertices y^2-x^2= 1/36 is (0, 1/6),(0,-1/6)

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vertices y^2-x^2= 1/36

vertices

y^{2} - x^{2} = \frac{1}{36}

(0, \frac{1}{6}), (0, - \frac{1}{6})

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

y^{2} - x^{2} = \frac{1}{36} :

Up-down Hyperbola with

(h, k) = (0, 0), a = \frac{1}{6}, b = \frac{1}{6}

(0, 0 + \frac{1}{6}), (0, 0 - \frac{1}{6})

Refine

(0, \frac{1}{6}), (0, - \frac{1}{6})

\frac{x ^{2}}{25} - \frac{y ^{2}}{81} = 1

\frac{( x - 3 ) ^{2}}{9} - \frac{( y + 4 ) ^{2}}{4} = 1

+ \frac{( y - 2 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{16} = 1

- 4 x^{2} + y^{2} = 4

4 x^{2} - y^{2} - 16 x - 6 y - 9 = 0

What is the vertices y^2-x^2= 1/36 ?
The vertices y^2-x^2= 1/36 is (0, 1/6),(0,-1/6)