What is the vertices (x^2)/4-(y^2)/1 =1 ?

The vertices (x^2)/4-(y^2)/1 =1 is (2,0),(-2,0)

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vertices (x^2)/4-(y^2)/1 =1

vertices

\frac{x ^{2}}{4} - \frac{y ^{2}}{1} = 1

(2, 0), (- 2, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{4} - \frac{y ^{2}}{1} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 1

(0 + 2, 0), (0 - 2, 0)

Refine

(2, 0), (- 2, 0)

y^{2} - x^{2} = 25

\frac{( y - 8 ) ^{2}}{4} - \frac{( x - 5 ) ^{2}}{9} = 1

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0

- 4 x^{2} + y^{2} = 16

x^{2} - y^{2} + 6 x - 4 y - 4 = 0

What is the vertices (x^2)/4-(y^2)/1 =1 ?
The vertices (x^2)/4-(y^2)/1 =1 is (2,0),(-2,0)