What is the vertices ((y-8)^2)/4-((x-5)^2)/9 =1 ?

The vertices ((y-8)^2)/4-((x-5)^2)/9 =1 is (5,10),(5,6)

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vertices ((y-8)^2)/4-((x-5)^2)/9 =1

vertices

\frac{( y - 8 ) ^{2}}{4} - \frac{( x - 5 ) ^{2}}{9} = 1

(5, 10), (5, 6)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{( y - 8 ) ^{2}}{4} - \frac{( x - 5 ) ^{2}}{9} = 1 :

Up-down Hyperbola with

(h, k) = (5, 8), a = 2, b = 3

(5, 8 + 2), (5, 8 - 2)

Refine

(5, 10), (5, 6)

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0

- 4 x^{2} + y^{2} = 16

x^{2} - y^{2} + 6 x - 4 y - 4 = 0

16 x^{2} - 9 y^{2} - 64 x - 18 y + 199 = 0

\frac{x ^{2}}{36} - \frac{y ^{2}}{81} = 1

What is the vertices ((y-8)^2)/4-((x-5)^2)/9 =1 ?
The vertices ((y-8)^2)/4-((x-5)^2)/9 =1 is (5,10),(5,6)