What is the vertices (x^2)/(45)-(y^2)/(360)=1 ?

The vertices (x^2)/(45)-(y^2)/(360)=1 is (3sqrt(5),0),(-3sqrt(5),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices (x^2)/(45)-(y^2)/(360)=1

vertices

\frac{x ^{2}}{45} - \frac{y ^{2}}{360} = 1

(35, 0), (- 35, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{45} - \frac{y ^{2}}{360} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 35, b = 610

(0 + 35, 0), (0 - 35, 0)

Refine

(35, 0), (- 35, 0)

49 x^{2} - 25 y^{2} - 686 x - 50 y + 2375 = 0

\frac{( x ^{2} )}{4} - \frac{( y ^{2} )}{9} = 1

16 y^{2} - 25 x^{2} = 400

\frac{( x - 6 ) ^{2}}{48} - (y - 2)^{2} = 1

x^{2} - \frac{y ^{2}}{25} = 1

What is the vertices (x^2)/(45)-(y^2)/(360)=1 ?
The vertices (x^2)/(45)-(y^2)/(360)=1 is (3sqrt(5),0),(-3sqrt(5),0)