What is the vertices x^2-(y^2)/(25)=1 ?

The vertices x^2-(y^2)/(25)=1 is (1,0),(-1,0)

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vertices x^2-(y^2)/(25)=1

vertices

x^{2} - \frac{y ^{2}}{25} = 1

(1, 0), (- 1, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

x^{2} - \frac{y ^{2}}{25} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 1, b = 5

(0 + 1, 0), (0 - 1, 0)

Refine

(1, 0), (- 1, 0)

\frac{x ^{2}}{49} - \frac{y ^{2}}{4} = 1

y^{2} - 25 x^{2} + 8 y - 9 = 0

x^{2} - 16 y^{2} = 144

25 x^{2} - 16 y^{2} + 50 x - 32 y - 391 = 0

\frac{x ^{2}}{49} - \frac{( y + 6 ) ^{2}}{4} = 1

What is the vertices x^2-(y^2)/(25)=1 ?
The vertices x^2-(y^2)/(25)=1 is (1,0),(-1,0)