What is the vertices (y^2)/(64)-(x^2)/(36)=1 ?

The vertices (y^2)/(64)-(x^2)/(36)=1 is (0,8),(0,-8)

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vertices (y^2)/(64)-(x^2)/(36)=1

vertices

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

(0, 8), (0, - 8)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 8, b = 6

(0, 0 + 8), (0, 0 - 8)

Refine

(0, 8), (0, - 8)

4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0

\frac{y ^{2}}{1} - \frac{x ^{2}}{15} = 1

4 y^{2} - 49 x^{2} - 392 x + 16 y - 964 = 0

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23

25 x^{2} - 9 y^{2} = 225

What is the vertices (y^2)/(64)-(x^2)/(36)=1 ?
The vertices (y^2)/(64)-(x^2)/(36)=1 is (0,8),(0,-8)