What is the vertices (y^2)/1-(x^2)/(15)=1 ?

The vertices (y^2)/1-(x^2)/(15)=1 is (0,1),(0,-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices (y^2)/1-(x^2)/(15)=1

vertices

\frac{y ^{2}}{1} - \frac{x ^{2}}{15} = 1

(0, 1), (0, - 1)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{1} - \frac{x ^{2}}{15} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 1, b = 15

(0, 0 + 1), (0, 0 - 1)

Refine

(0, 1), (0, - 1)

4 y^{2} - 49 x^{2} - 392 x + 16 y - 964 = 0

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23

25 x^{2} - 9 y^{2} = 225

3 x^{2} - 15 y^{2} + 2 x - 3 y = 4

\frac{y ^{2}}{4} - \frac{x ^{2}}{9} = 1

What is the vertices (y^2)/1-(x^2)/(15)=1 ?
The vertices (y^2)/1-(x^2)/(15)=1 is (0,1),(0,-1)