What is (x-4)^2-(y-4)^2<= 9 ?

The solution to (x-4)^2-(y-4)^2<= 9 is Hyperbola with (h,k)=(4,4),a=3,b=3

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(x-4)^2-(y-4)^2<= 9

(x - 4)^{2} - (y - 4)^{2} \leq 9

(h, k) = (4, 4), a = 3, b = 3

Solution steps

(x - 4)^{2} - (y - 4)^{2} \leq 9

Rewrite

(x - 4)^{2} - (y - 4)^{2} \leq 9

in the form of a standard hyperbola equation

\frac{( x - 4 ) ^{2}}{3 ^{2}} - \frac{( y - 4 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, 4), a = 3, b = 3

x^{2} + x = y^{2}

\frac{( x ^{(2)} )}{( 9 )} - \frac{( y ^{(2)} )}{( 16 )} = 1

y^{2} - 4 z^{2} = 4

- \frac{y ^{2}}{4} + \frac{z ^{2}}{4} = 1

\frac{( y + 2 ) ^{2}}{4} - \frac{( x - 1 ) ^{2}}{64} = 1

What is (x-4)^2-(y-4)^2<= 9 ?
The solution to (x-4)^2-(y-4)^2<= 9 is Hyperbola with (h,k)=(4,4),a=3,b=3