What is ((y+2)^2)/4-((x-1)^2)/(64)=1 ?

The solution to ((y+2)^2)/4-((x-1)^2)/(64)=1 is Hyperbola with (h,k)=(1,-2),a=2,b=8

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((y+2)^2)/4-((x-1)^2)/(64)=1

\frac{( y + 2 ) ^{2}}{4} - \frac{( x - 1 ) ^{2}}{64} = 1

(h, k) = (1, - 2), a = 2, b = 8

Solution steps

\frac{( y + 2 ) ^{2}}{4} - \frac{( x - 1 ) ^{2}}{64} = 1

Rewrite

\frac{( y + 2 ) ^{2}}{4} - \frac{( x - 1 ) ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{2 ^{2}} - \frac{( x - 1 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 2, b = 8

(y - 1)^{2} - 9 (x - 2)^{2} = 9

y^{2} = (- x)^{2} + 6

\frac{4 b - 4 a}{b - a} = (a^{2} - b^{2})

\frac{x ^{2}}{25} - y^{2} = 1

\frac{( x - 3 ) ^{2}}{49} - \frac{( y + 5 ) ^{2}}{25} = 1

What is ((y+2)^2)/4-((x-1)^2)/(64)=1 ?
The solution to ((y+2)^2)/4-((x-1)^2)/(64)=1 is Hyperbola with (h,k)=(1,-2),a=2,b=8