What is (x-0)^2-(y-4)^2=1 ?

The solution to (x-0)^2-(y-4)^2=1 is Hyperbola with (h,k)=(0,4),a=1,b=1

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(x-0)^2-(y-4)^2=1

(x - 0)^{2} - (y - 4)^{2} = 1

(h, k) = (0, 4), a = 1, b = 1

Solution steps

(x - 0)^{2} - (y - 4)^{2} = 1

Rewrite

(x - 0)^{2} - (y - 4)^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} - \frac{( y - 4 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 4), a = 1, b = 1

(x - 0)^{2} - (y - 4)^{2} = 2

\frac{( y - 4 ) ^{2}}{16} - \frac{( x + 3 ) ^{2}}{36} = 1

\frac{y}{4 x ^{2} - 9 y ^{2}} = 36

\frac{( x - 7 ) ^{2}}{16} - \frac{y ^{2}}{9} = 1

16 x^{2} - 32 x = 9 y^{2} + 144 y - 16

What is (x-0)^2-(y-4)^2=1 ?
The solution to (x-0)^2-(y-4)^2=1 is Hyperbola with (h,k)=(0,4),a=1,b=1