What is (x-0)^2-(y-4)^2=2 ?

The solution to (x-0)^2-(y-4)^2=2 is Hyperbola with (h,k)=(0,4),a=sqrt(2),b=sqrt(2)

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(x-0)^2-(y-4)^2=2

(x - 0)^{2} - (y - 4)^{2} = 2

(h, k) = (0, 4), a = 2, b = 2

Solution steps

(x - 0)^{2} - (y - 4)^{2} = 2

Rewrite

(x - 0)^{2} - (y - 4)^{2} = 2

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 ) ^{2}} - \frac{( y - 4 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 4), a = 2, b = 2

\frac{( y - 4 ) ^{2}}{16} - \frac{( x + 3 ) ^{2}}{36} = 1

\frac{y}{4 x ^{2} - 9 y ^{2}} = 36

\frac{( x - 7 ) ^{2}}{16} - \frac{y ^{2}}{9} = 1

16 x^{2} - 32 x = 9 y^{2} + 144 y - 16

y^{(2)} - x^{(2)} = (\frac{1}{49})

What is (x-0)^2-(y-4)^2=2 ?
The solution to (x-0)^2-(y-4)^2=2 is Hyperbola with (h,k)=(0,4),a=sqrt(2),b=sqrt(2)