What is ((x-3)^2)/4-(y^2)/9 =1 ?

The solution to ((x-3)^2)/4-(y^2)/9 =1 is Hyperbola with (h,k)=(3,0),a=2,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-3)^2)/4-(y^2)/9 =1

\frac{( x - 3 ) ^{2}}{4} - \frac{y ^{2}}{9} = 1

(h, k) = (3, 0), a = 2, b = 3

Solution steps

\frac{( x - 3 ) ^{2}}{4} - \frac{y ^{2}}{9} = 1

Rewrite

\frac{( x - 3 ) ^{2}}{4} - \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 0), a = 2, b = 3

- 16 x^{2} + 4 y^{2} - 32 x + 16 y - 64 = 0

4 x^{2} - 16 x - 9 y^{2} = 20

\frac{17}{x + y} \frac{5}{x - y} = 5

\frac{( y - 3 ) ^{2}}{81} - \frac{( x + 5 ) ^{2}}{144} = 1

(\frac{y ^{2}}{4}) - (\frac{x ^{2}}{16}) = 1

What is ((x-3)^2)/4-(y^2)/9 =1 ?
The solution to ((x-3)^2)/4-(y^2)/9 =1 is Hyperbola with (h,k)=(3,0),a=2,b=3