What is -16x^2+4y^2-32x+16y-64=0 ?

The solution to -16x^2+4y^2-32x+16y-64=0 is Hyperbola with (h,k)=(-1,-2),a=4,b=2

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-16x^2+4y^2-32x+16y-64=0

- 16 x^{2} + 4 y^{2} - 32 x + 16 y - 64 = 0

(h, k) = (- 1, - 2), a = 4, b = 2

Solution steps

- 16 x^{2} + 4 y^{2} - 32 x + 16 y - 64 = 0

Rewrite

- 16 x^{2} + 4 y^{2} - 32 x + 16 y - 64 = 0

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{4 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, - 2), a = 4, b = 2

4 x^{2} - 16 x - 9 y^{2} = 20

\frac{17}{x + y} \frac{5}{x - y} = 5

\frac{( y - 3 ) ^{2}}{81} - \frac{( x + 5 ) ^{2}}{144} = 1

(\frac{y ^{2}}{4}) - (\frac{x ^{2}}{16}) = 1

\frac{( x - 3 ) ^{2}}{16} - \frac{y ^{2}}{4} = 1

What is -16x^2+4y^2-32x+16y-64=0 ?
The solution to -16x^2+4y^2-32x+16y-64=0 is Hyperbola with (h,k)=(-1,-2),a=4,b=2