What is ((x+1)^2}{16}-\frac{(y-2)^2)/9 =1 ?

The solution to ((x+1)^2}{16}-\frac{(y-2)^2)/9 =1 is Hyperbola with (h,k)=(-1,2),a=4,b=3

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((x+1)^2}{16}-\frac{(y-2)^2)/9 =1

\frac{( x + 1 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{9} = 1

(h, k) = (- 1, 2), a = 4, b = 3

Solution steps

\frac{( x + 1 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{9} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{4 ^{2}} - \frac{( y - 2 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 2), a = 4, b = 3

x^{2} - y^{2} - 6 x - 7 = 0

x^{(2)} - 6 = \frac{( y ^{(2)} )}{( 3 )}

\frac{x ^{2}}{9} + \frac{2 x}{3} - 9 y^{2} - 54 y - 81 = 0

\frac{1}{36} x^{2} - \frac{1}{4} y^{2} = 1

\frac{x ^{2}}{32} - \frac{y ^{2}}{25} = 1

What is ((x+1)^2}{16}-\frac{(y-2)^2)/9 =1 ?
The solution to ((x+1)^2}{16}-\frac{(y-2)^2)/9 =1 is Hyperbola with (h,k)=(-1,2),a=4,b=3