What is (x^2)/(32)-(y^2)/(25)=1 ?

The solution to (x^2)/(32)-(y^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=4sqrt(2),b=5

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(x^2)/(32)-(y^2)/(25)=1

\frac{x ^{2}}{32} - \frac{y ^{2}}{25} = 1

(h, k) = (0, 0), a = 42, b = 5

Solution steps

\frac{x ^{2}}{32} - \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{32} - \frac{y ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 4 2 ) ^{2}} - \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 42, b = 5

yy = x^{2} - 9

4 x^{2} - y^{2} - 4 = 0

x^{2} - 9 y^{2} = 36

50 y^{2} - 25 x^{2} + 100 x - 100 y - 75 = 0

144 y^{(2)} - 25 x^{(2)} = 3600

What is (x^2)/(32)-(y^2)/(25)=1 ?
The solution to (x^2)/(32)-(y^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=4sqrt(2),b=5