What is ((y-4)^2)/(49)-((x+5)^2)/(16)=1 ?

The solution to ((y-4)^2)/(49)-((x+5)^2)/(16)=1 is Hyperbola with (h,k)=(-5,4),a=7,b=4

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((y-4)^2)/(49)-((x+5)^2)/(16)=1

\frac{( y - 4 ) ^{2}}{49} - \frac{( x + 5 ) ^{2}}{16} = 1

(h, k) = (- 5, 4), a = 7, b = 4

Solution steps

\frac{( y - 4 ) ^{2}}{49} - \frac{( x + 5 ) ^{2}}{16} = 1

Rewrite

\frac{( y - 4 ) ^{2}}{49} - \frac{( x + 5 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{7 ^{2}} - \frac{( x - ( - 5 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 4), a = 7, b = 4

\frac{( y + 3 ) ^{2}}{9} - \frac{4 ( x + 2 ) ^{2}}{25} = 1

y^{2} - z^{2} = 16

y^{2} = x^{2} + 169

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

\frac{( y - 4 ) ^{2}}{28} - \frac{( x + 1 ) ^{2}}{21} = 1

What is ((y-4)^2)/(49)-((x+5)^2)/(16)=1 ?
The solution to ((y-4)^2)/(49)-((x+5)^2)/(16)=1 is Hyperbola with (h,k)=(-5,4),a=7,b=4