What is ((y-4)^2)/(28)-((x+1)^2)/(21)=1 ?

The solution to ((y-4)^2)/(28)-((x+1)^2)/(21)=1 is Hyperbola with (h,k)=(-1,4),a=2sqrt(7),b=sqrt(21)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y-4)^2)/(28)-((x+1)^2)/(21)=1

\frac{( y - 4 ) ^{2}}{28} - \frac{( x + 1 ) ^{2}}{21} = 1

(h, k) = (- 1, 4), a = 27, b = 21

Solution steps

\frac{( y - 4 ) ^{2}}{28} - \frac{( x + 1 ) ^{2}}{21} = 1

Rewrite

\frac{( y - 4 ) ^{2}}{28} - \frac{( x + 1 ) ^{2}}{21} = 1

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{( 2 7 ) ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{( 21 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 4), a = 27, b = 21

\frac{( y + 9 ) ^{2}}{92} - \frac{( x + 8 ) ^{2}}{36} = 17

\frac{x ^{2}}{6} - \frac{y ^{2}}{8} = 1

16 x^{2} - 96 x - 9 y^{2} - 18 y - 9 = 0

(r - 4)^{2} = (t + 4)^{2} + 32

x^{2} - y^{2} - 2 x - 8 y - 8 = 0

What is ((y-4)^2)/(28)-((x+1)^2)/(21)=1 ?
The solution to ((y-4)^2)/(28)-((x+1)^2)/(21)=1 is Hyperbola with (h,k)=(-1,4),a=2sqrt(7),b=sqrt(21)