What is ((y^2)}{25}-\frac{(x^2))/9 =1 ?

The solution to ((y^2)}{25}-\frac{(x^2))/9 =1 is Hyperbola with (h,k)=(0,0),a=5,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y^2)}{25}-\frac{(x^2))/9 =1

\frac{( y ^{2} )}{25} - \frac{( x ^{2} )}{9} = 1

(h, k) = (0, 0), a = 5, b = 3

Solution steps

\frac{y ^{2}}{25} - \frac{x ^{2}}{9} = 1

Rewrite

\frac{y ^{2}}{25} - \frac{x ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{5 ^{2}} - \frac{( x - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 3

4 x^{2} - 25 y^{2} + 48 + 150 - 181 = 0

9 y^{2} + 36 y - 4 x^{2} - 16 x - 16 = 0

\frac{x ^{2}}{56} - \frac{y ^{2}}{20} = 1

\frac{( x + 2 ) ^{2}}{16} - \frac{( y + 3 ) ^{2}}{9} = 1

\frac{( y - 4 ) ^{2}}{48} - \frac{( x + 1 ) ^{2}}{9} = 1

What is ((y^2)}{25}-\frac{(x^2))/9 =1 ?
The solution to ((y^2)}{25}-\frac{(x^2))/9 =1 is Hyperbola with (h,k)=(0,0),a=5,b=3