What is (x^2)/(56)-(y^2)/(20)=1 ?

The solution to (x^2)/(56)-(y^2)/(20)=1 is Hyperbola with (h,k)=(0,0),a=2sqrt(14),b=2sqrt(5)

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(x^2)/(56)-(y^2)/(20)=1

\frac{x ^{2}}{56} - \frac{y ^{2}}{20} = 1

(h, k) = (0, 0), a = 214, b = 25

Solution steps

\frac{x ^{2}}{56} - \frac{y ^{2}}{20} = 1

Rewrite

\frac{x ^{2}}{56} - \frac{y ^{2}}{20} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 14 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 5 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 214, b = 25

\frac{( x + 2 ) ^{2}}{16} - \frac{( y + 3 ) ^{2}}{9} = 1

\frac{( y - 4 ) ^{2}}{48} - \frac{( x + 1 ) ^{2}}{9} = 1

25 y^{(2)} - 16 x^{(2)} - 400 = 0

- x^{2} + 4 y^{2} = 4

(x - 4)^{2} - (y + 1)^{2} = 4

What is (x^2)/(56)-(y^2)/(20)=1 ?
The solution to (x^2)/(56)-(y^2)/(20)=1 is Hyperbola with (h,k)=(0,0),a=2sqrt(14),b=2sqrt(5)