What is ((y+3)^2)/1-((x+2)^2)/3 =1 ?

The solution to ((y+3)^2)/1-((x+2)^2)/3 =1 is Hyperbola with (h,k)=(-2,-3),a=1,b=sqrt(3)

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((y+3)^2)/1-((x+2)^2)/3 =1

\frac{( y + 3 ) ^{2}}{1} - \frac{( x + 2 ) ^{2}}{3} = 1

(h, k) = (- 2, - 3), a = 1, b = 3

Solution steps

\frac{( y + 3 ) ^{2}}{1} - \frac{( x + 2 ) ^{2}}{3} = 1

Rewrite

\frac{( y + 3 ) ^{2}}{1} - \frac{( x + 2 ) ^{2}}{3} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 3 ) ) ^{2}}{1 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, - 3), a = 1, b = 3

1 = aa - bb

25 x^{2} - 36 y^{2} - 150 x - 288 y - 1251 = 0

x^{2} + y^{2} + 5 x + y - 26 = 0.2 x^{2} + 2 y^{2} - 4 x + 9 y + 4

\frac{x ^{2}}{2} - \frac{y ^{2}}{1} = 1

16 x^{2} - 128 x - y^{2} - 12 y + 224 = 0

What is ((y+3)^2)/1-((x+2)^2)/3 =1 ?
The solution to ((y+3)^2)/1-((x+2)^2)/3 =1 is Hyperbola with (h,k)=(-2,-3),a=1,b=sqrt(3)