What is 16x^2-128x-y^2-12y+224=0 ?

The solution to 16x^2-128x-y^2-12y+224=0 is Hyperbola with (h,k)=(4,-6),a=2,b= 1/2

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16x^2-128x-y^2-12y+224=0

16 x^{2} - 128 x - y^{2} - 12 y + 224 = 0

(h, k) = (4, - 6), a = 2, b = \frac{1}{2}

Solution steps

16 x^{2} - 128 x - y^{2} - 12 y + 224 = 0

Rewrite

16 x^{2} - 128 x - y^{2} - 12 y + 224 = 0

in the form of a standard hyperbola equation

\frac{( y - ( - 6 ) ) ^{2}}{2 ^{2}} - \frac{( x - 4 ) ^{2}}{( \frac{1}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, - 6), a = 2, b = \frac{1}{2}

3 y^{2} - x^{2} + 6 x - 12 = 0

- \frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

\frac{x ^{2}}{1 ^{2}} - \frac{z ^{2}}{2 ^{2}} = 1

x^{2} - 4 y^{2} + 2 x - 32 y - 67 = 0

\frac{x ^{2} - y ^{2}}{3} = 1

What is 16x^2-128x-y^2-12y+224=0 ?
The solution to 16x^2-128x-y^2-12y+224=0 is Hyperbola with (h,k)=(4,-6),a=2,b= 1/2