What is -x^2+y^2=12 ?

The solution to -x^2+y^2=12 is Hyperbola with (h,k)=(0,0),a=2sqrt(3),b=2sqrt(3)

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-x^2+y^2=12

- x^{2} + y^{2} = 12

(h, k) = (0, 0), a = 23, b = 23

Solution steps

- x^{2} + y^{2} = 12

Rewrite

- x^{2} + y^{2} = 12

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( 2 3 ) ^{2}} - \frac{( x - 0 ) ^{2}}{( 2 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 23, b = 23

\frac{x ^{2}}{8} - \frac{y ^{2}}{4} = 1

\frac{( y + 3 ) ^{2}}{64} - \frac{( x + 6 ) ^{2}}{49} = 1

2 x^{2} - 3 y^{2} - x + y = 0

\frac{( x - 2 ) ^{2}}{4} - \frac{y ^{2}}{9} = 1

2 a - 3 b^{2} = 4 a^{2} - 9 b^{2}

What is -x^2+y^2=12 ?
The solution to -x^2+y^2=12 is Hyperbola with (h,k)=(0,0),a=2sqrt(3),b=2sqrt(3)