What is ((y+3)^2)/(64)-((x+6)^2)/(49)=1 ?

The solution to ((y+3)^2)/(64)-((x+6)^2)/(49)=1 is Hyperbola with (h,k)=(-6,-3),a=8,b=7

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((y+3)^2)/(64)-((x+6)^2)/(49)=1

\frac{( y + 3 ) ^{2}}{64} - \frac{( x + 6 ) ^{2}}{49} = 1

(h, k) = (- 6, - 3), a = 8, b = 7

Solution steps

\frac{( y + 3 ) ^{2}}{64} - \frac{( x + 6 ) ^{2}}{49} = 1

Rewrite

\frac{( y + 3 ) ^{2}}{64} - \frac{( x + 6 ) ^{2}}{49} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 3 ) ) ^{2}}{8 ^{2}} - \frac{( x - ( - 6 ) ) ^{2}}{7 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 6, - 3), a = 8, b = 7

2 x^{2} - 3 y^{2} - x + y = 0

\frac{( x - 2 ) ^{2}}{4} - \frac{y ^{2}}{9} = 1

2 a - 3 b^{2} = 4 a^{2} - 9 b^{2}

\frac{( y - 4 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

9 x^{2} - 36 x - y^{2} - 6 y + 18 = 0

What is ((y+3)^2)/(64)-((x+6)^2)/(49)=1 ?
The solution to ((y+3)^2)/(64)-((x+6)^2)/(49)=1 is Hyperbola with (h,k)=(-6,-3),a=8,b=7