What is ((y-6)^2)/(49)-((x+2)^2)/(64)=1 ?

The solution to ((y-6)^2)/(49)-((x+2)^2)/(64)=1 is Hyperbola with (h,k)=(-2,6),a=7,b=8

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((y-6)^2)/(49)-((x+2)^2)/(64)=1

\frac{( y - 6 ) ^{2}}{49} - \frac{( x + 2 ) ^{2}}{64} = 1

(h, k) = (- 2, 6), a = 7, b = 8

Solution steps

\frac{( y - 6 ) ^{2}}{49} - \frac{( x + 2 ) ^{2}}{64} = 1

Rewrite

\frac{( y - 6 ) ^{2}}{49} - \frac{( x + 2 ) ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( y - 6 ) ^{2}}{7 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 6), a = 7, b = 8

9 y^{2} - 4 x^{2} - 18 y + 24 x - 63 = 0

2 x^{2} - 4 y^{2} = 4^{2}

x^{2} + 4 x + 4 - 9 y^{2} = 5

\frac{( y + 2 ) ^{2}}{25} - \frac{( x - 1 ) ^{2}}{9} = 1

4 x^{2} - 3 y^{2} - 12 = 0

What is ((y-6)^2)/(49)-((x+2)^2)/(64)=1 ?
The solution to ((y-6)^2)/(49)-((x+2)^2)/(64)=1 is Hyperbola with (h,k)=(-2,6),a=7,b=8