What is x^2+4x+4-9y^2=5 ?

The solution to x^2+4x+4-9y^2=5 is Hyperbola with (h,k)=(-2,0),a=sqrt(5),b=(sqrt(5))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+4x+4-9y^2=5

x^{2} + 4 x + 4 - 9 y^{2} = 5

(h, k) = (- 2, 0), a = 5, b = \frac{5}{3}

Solution steps

x^{2} + 4 x + 4 - 9 y^{2} = 5

Rewrite

x^{2} + 4 x + 4 - 9 y^{2} = 5

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{( 5 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( \frac{5}{3} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 0), a = 5, b = \frac{5}{3}

\frac{( y + 2 ) ^{2}}{25} - \frac{( x - 1 ) ^{2}}{9} = 1

4 x^{2} - 3 y^{2} - 12 = 0

2 x^{2} - y^{2} = - 8

x^{2} - y^{2} + 4 x - 2 y - 5 = 0

\frac{x ^{2}}{1} - \frac{y ^{2}}{15} = 1

What is x^2+4x+4-9y^2=5 ?
The solution to x^2+4x+4-9y^2=5 is Hyperbola with (h,k)=(-2,0),a=sqrt(5),b=(sqrt(5))/3