s^2=d^2+2^2

解答

s^{2} = d^{2} + 2^{2}

(h, k) = (0, 0), a = 2, b = 2

求解步骤

s^{2} = d^{2} + 2^{2}

将

s^{2} = d^{2} + 2^{2}

改写为标准双曲线方程形式

\frac{( s - 0 ) ^{2}}{2 ^{2}} - \frac{( d - 0 ) ^{2}}{2 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (0, 0), a = 2, b = 2

2 x^{(2)} - 4 y^{(2)} = 16

4 x^{2} - 25 y^{2} + 8 x - 100 y - 196 = 0

so l v e f or x, x \cdot (x + 1) = h (x)^{2}

- x^{2} + 2 y^{2} - 20 y - 6 = 0

\frac{( x - 1 ) ^{2}}{64} - \frac{( y - 2 ) ^{2}}{32} = 1