What is ((x^2)/(36))-(y^2)/(25)=1 ?

The solution to ((x^2)/(36))-(y^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=6,b=5

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((x^2)/(36))-(y^2)/(25)=1

(\frac{x ^{2}}{36}) - \frac{y ^{2}}{25} = 1

(h, k) = (0, 0), a = 6, b = 5

Solution steps

\frac{x ^{2}}{36} - \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{36} - \frac{y ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} - \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 6, b = 5

\frac{y ^{2}}{4} - \frac{x ^{2}}{1} = 1

- 4 x^{2} + 5 y^{2} + 8 x - 30 y + 21 = 0

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{9} = 1

16 x^{2} - 96 x - 25 y^{2} + 200 y - 656 = 0

y^{2} = x^{2} + 17

What is ((x^2)/(36))-(y^2)/(25)=1 ?
The solution to ((x^2)/(36))-(y^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=6,b=5