What is ((y+2)^2)/(3^2)-((x-5)^2)/(5^2)=1 ?

The solution to ((y+2)^2)/(3^2)-((x-5)^2)/(5^2)=1 is Hyperbola with (h,k)=(5,-2),a=3,b=5

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((y+2)^2)/(3^2)-((x-5)^2)/(5^2)=1

\frac{( y + 2 ) ^{2}}{3 ^{2}} - \frac{( x - 5 ) ^{2}}{5 ^{2}} = 1

(h, k) = (5, - 2), a = 3, b = 5

Solution steps

\frac{( y + 2 ) ^{2}}{3 ^{2}} - \frac{( x - 5 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, - 2), a = 3, b = 5

x^{2} - y^{2} + 4 x + 16 y - 69 = 0

- \frac{36 ( x - 3 ) ^{2}}{1} + \frac{25 ( y - 4 ) ^{2}}{1} = 900

x^{2} - 5 y^{2} = 3

\frac{( y + 5 ) ^{2}}{100} - \frac{( x - 4 ) ^{2}}{121} = 1

1 0^{2} + x^{2} = y^{2}

What is ((y+2)^2)/(3^2)-((x-5)^2)/(5^2)=1 ?
The solution to ((y+2)^2)/(3^2)-((x-5)^2)/(5^2)=1 is Hyperbola with (h,k)=(5,-2),a=3,b=5