What is x^2-y^2+4x+16y-69=0 ?

The solution to x^2-y^2+4x+16y-69=0 is Hyperbola with (h,k)=(-2,8),a=3,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-y^2+4x+16y-69=0

x^{2} - y^{2} + 4 x + 16 y - 69 = 0

(h, k) = (- 2, 8), a = 3, b = 3

Solution steps

x^{2} - y^{2} + 4 x + 16 y - 69 = 0

Rewrite

x^{2} - y^{2} + 4 x + 16 y - 69 = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{3 ^{2}} - \frac{( y - 8 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 8), a = 3, b = 3

- \frac{36 ( x - 3 ) ^{2}}{1} + \frac{25 ( y - 4 ) ^{2}}{1} = 900

x^{2} - 5 y^{2} = 3

\frac{( y + 5 ) ^{2}}{100} - \frac{( x - 4 ) ^{2}}{121} = 1

1 0^{2} + x^{2} = y^{2}

8 y^{2} - x^{2} - 16 y + 8 x - 16 = 0

What is x^2-y^2+4x+16y-69=0 ?
The solution to x^2-y^2+4x+16y-69=0 is Hyperbola with (h,k)=(-2,8),a=3,b=3