What is 9x^2-4y-54x-8y+113=0 ?

The solution to 9x^2-4y-54x-8y+113=0 is Parabola with (h,k)=(3, 8/3),p= 1/3

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9x^2-4y-54x-8y+113=0

9 x^{2} - 4 y - 54 x - 8 y + 113 = 0

(h, k) = (3, \frac{8}{3}), p = \frac{1}{3}

Solution steps

9 x^{2} - 4 y - 54 x - 8 y + 113 = 0

Rewrite

9 x^{2} - 4 y - 54 x - 8 y + 113 = 0

in the standard form

4 \cdot \frac{1}{3} (y - \frac{8}{3}) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, \frac{8}{3}), p = \frac{1}{3}

x = 9 y^{2}

y^{2} = 6 x - 4 y - 12

\frac{a + b}{2} - \frac{a}{b} = a - \frac{a + b}{2}

x^{2} - 16 y - 9 x + 83 = 0

4 x^{2} + 2 y = 0

What is 9x^2-4y-54x-8y+113=0 ?
The solution to 9x^2-4y-54x-8y+113=0 is Parabola with (h,k)=(3, 8/3),p= 1/3