What is (a+b)/2-a/b =a-(a+b)/2 ?

The solution to (a+b)/2-a/b =a-(a+b)/2 is Parabola with (h,k)=(0,0),p= 1/4

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(a+b)/2-a/b =a-(a+b)/2

\frac{a + b}{2} - \frac{a}{b} = a - \frac{a + b}{2}

(h, k) = (0, 0), p = \frac{1}{4}

Solution steps

\frac{a + b}{2} - \frac{a}{b} = a - \frac{a + b}{2}

Rewrite

\frac{a + b}{2} - \frac{a}{b} - a + \frac{a + b}{2} = 0

in the standard form

4 \cdot \frac{1}{4} (a - 0) = (b - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

x^{2} - 16 y - 9 x + 83 = 0

4 x^{2} + 2 y = 0

y \geq (x - 1)^{2}

x^{2} + 2 x + k (x) = 0

x^{2} + 6 x + 16 y + 121 = 0

What is (a+b)/2-a/b =a-(a+b)/2 ?
The solution to (a+b)/2-a/b =a-(a+b)/2 is Parabola with (h,k)=(0,0),p= 1/4