What is ((y+1)^2)/9-((x+1)^2)/(16)=1 ?

The solution to ((y+1)^2)/9-((x+1)^2)/(16)=1 is Hyperbola with (h,k)=(-1,-1),a=3,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y+1)^2)/9-((x+1)^2)/(16)=1

\frac{( y + 1 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{16} = 1

(h, k) = (- 1, - 1), a = 3, b = 4

Solution steps

\frac{( y + 1 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{16} = 1

Rewrite

\frac{( y + 1 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, - 1), a = 3, b = 4

\frac{x ^{2}}{7} - \frac{7 y ^{2}}{42} = 1

\frac{( x - 3 ) ^{2}}{64} - \frac{( y + 2 ) ^{2}}{16} = 1

\frac{x ^{2}}{36} - \frac{y ^{2}}{49} = 1

x^{2} - y^{2} - 6 x - 4 y + 7 = 0

3 x^{2} + 2 x + 92 = 3 y^{2}

What is ((y+1)^2)/9-((x+1)^2)/(16)=1 ?
The solution to ((y+1)^2)/9-((x+1)^2)/(16)=1 is Hyperbola with (h,k)=(-1,-1),a=3,b=4