What is (x^2)/7-(7y^2)/(42)=1 ?

The solution to (x^2)/7-(7y^2)/(42)=1 is Hyperbola with (h,k)=(0,0),a=sqrt(7),b=sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2)/7-(7y^2)/(42)=1

\frac{x ^{2}}{7} - \frac{7 y ^{2}}{42} = 1

(h, k) = (0, 0), a = 7, b = 6

Solution steps

\frac{x ^{2}}{7} - \frac{7 y ^{2}}{42} = 1

Rewrite

\frac{x ^{2}}{7} - \frac{7 y ^{2}}{42} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 7 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 6 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 7, b = 6

\frac{( x - 3 ) ^{2}}{64} - \frac{( y + 2 ) ^{2}}{16} = 1

\frac{x ^{2}}{36} - \frac{y ^{2}}{49} = 1

x^{2} - y^{2} - 6 x - 4 y + 7 = 0

3 x^{2} + 2 x + 92 = 3 y^{2}

4 x^{2} - 4 y^{2} = 64

What is (x^2)/7-(7y^2)/(42)=1 ?
The solution to (x^2)/7-(7y^2)/(42)=1 is Hyperbola with (h,k)=(0,0),a=sqrt(7),b=sqrt(6)