What is -(x^2)/5+(y^2)/7 =1 ?

The solution to -(x^2)/5+(y^2)/7 =1 is Hyperbola with (h,k)=(0,0),a=sqrt(7),b=sqrt(5)

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-(x^2)/5+(y^2)/7 =1

- \frac{x ^{2}}{5} + \frac{y ^{2}}{7} = 1

(h, k) = (0, 0), a = 7, b = 5

Solution steps

- \frac{x ^{2}}{5} + \frac{y ^{2}}{7} = 1

Rewrite

- \frac{x ^{2}}{5} + \frac{y ^{2}}{7} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( 7 ) ^{2}} - \frac{( x - 0 ) ^{2}}{( 5 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 7, b = 5

x^{2} - y^{2} + 2 x + 4 y - 12 = 0

\frac{x ^{2}}{36} - \frac{y ^{2}}{13} = 1

\frac{x ^{2}}{36} - \frac{y ^{2}}{25} = 1

y^{2} - 4 y - 4 x^{2} + 13 = 0

16 y^{2} - x^{2} = 144

What is -(x^2)/5+(y^2)/7 =1 ?
The solution to -(x^2)/5+(y^2)/7 =1 is Hyperbola with (h,k)=(0,0),a=sqrt(7),b=sqrt(5)