What is (x^2)/(36)-(y^2)/(13)=1 ?

The solution to (x^2)/(36)-(y^2)/(13)=1 is Hyperbola with (h,k)=(0,0),a=6,b=sqrt(13)

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(x^2)/(36)-(y^2)/(13)=1

\frac{x ^{2}}{36} - \frac{y ^{2}}{13} = 1

(h, k) = (0, 0), a = 6, b = 13

Solution steps

\frac{x ^{2}}{36} - \frac{y ^{2}}{13} = 1

Rewrite

\frac{x ^{2}}{36} - \frac{y ^{2}}{13} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} - \frac{( y - 0 ) ^{2}}{( 13 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 6, b = 13

\frac{x ^{2}}{36} - \frac{y ^{2}}{25} = 1

y^{2} - 4 y - 4 x^{2} + 13 = 0

16 y^{2} - x^{2} = 144

\frac{x ^{2}}{5} - \frac{y ^{2}}{9} = 1

\frac{x}{y} - \frac{y}{x} = \frac{1}{y}

What is (x^2)/(36)-(y^2)/(13)=1 ?
The solution to (x^2)/(36)-(y^2)/(13)=1 is Hyperbola with (h,k)=(0,0),a=6,b=sqrt(13)