What is ((y+1)^2)/9-((x+3)^2)/4 =1 ?

The solution to ((y+1)^2)/9-((x+3)^2)/4 =1 is Hyperbola with (h,k)=(-3,-1),a=3,b=2

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((y+1)^2)/9-((x+3)^2)/4 =1

\frac{( y + 1 ) ^{2}}{9} - \frac{( x + 3 ) ^{2}}{4} = 1

(h, k) = (- 3, - 1), a = 3, b = 2

Solution steps

\frac{( y + 1 ) ^{2}}{9} - \frac{( x + 3 ) ^{2}}{4} = 1

Rewrite

\frac{( y + 1 ) ^{2}}{9} - \frac{( x + 3 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} - \frac{( x - ( - 3 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, - 1), a = 3, b = 2

16 x^{2} - 64 x - 9 y^{2} - 54 y + 1 = 0

\frac{y ^{2}}{1} - \frac{x ^{2}}{4} = 1

7 x^{2} - 9 y^{2} - 63 = 0

9 y^{2} - 4 x^{2} - 8 x - 12 y + 16 = 0

\frac{( x + 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{25} = 1

What is ((y+1)^2)/9-((x+3)^2)/4 =1 ?
The solution to ((y+1)^2)/9-((x+3)^2)/4 =1 is Hyperbola with (h,k)=(-3,-1),a=3,b=2