What is ((x+2)^2)/4-((y-1)^2)/(25)=1 ?

The solution to ((x+2)^2)/4-((y-1)^2)/(25)=1 is Hyperbola with (h,k)=(-2,1),a=2,b=5

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((x+2)^2)/4-((y-1)^2)/(25)=1

\frac{( x + 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{25} = 1

(h, k) = (- 2, 1), a = 2, b = 5

Solution steps

\frac{( x + 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{25} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{2 ^{2}} - \frac{( y - 1 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 1), a = 2, b = 5

x^{2} - 2 y^{2} = 3

x^{2} - y^{2} + 2 y = 2

x^{2} - 20 x - 4 y^{2} - 64 y - 172 = 0

5 x^{2} - 4 y^{2} = 20

x^{2} + (y - 5) = (y + 5)^{2}

What is ((x+2)^2)/4-((y-1)^2)/(25)=1 ?
The solution to ((x+2)^2)/4-((y-1)^2)/(25)=1 is Hyperbola with (h,k)=(-2,1),a=2,b=5