What is ((x-6)^2)/(36)-((y+1)^2)/(25)=1 ?

The solution to ((x-6)^2)/(36)-((y+1)^2)/(25)=1 is Hyperbola with (h,k)=(6,-1),a=6,b=5

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((x-6)^2)/(36)-((y+1)^2)/(25)=1

\frac{( x - 6 ) ^{2}}{36} - \frac{( y + 1 ) ^{2}}{25} = 1

(h, k) = (6, - 1), a = 6, b = 5

Solution steps

\frac{( x - 6 ) ^{2}}{36} - \frac{( y + 1 ) ^{2}}{25} = 1

Rewrite

\frac{( x - 6 ) ^{2}}{36} - \frac{( y + 1 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - 6 ) ^{2}}{6 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (6, - 1), a = 6, b = 5

x, (x - 0.5)^{2} + (x + 0.5)^{2} = r (x)^{2}

25 x^{2} - 16 y^{2} = 1

\frac{( x - 3 ) ^{2}}{6} - \frac{( y - 2 ) ^{2}}{2} = 1

(\frac{x + 1}{9})^{2} - (\frac{y - 3}{16})^{2} = 1

\frac{y ^{2}}{1} - \frac{x ^{2}}{9} = 1

What is ((x-6)^2)/(36)-((y+1)^2)/(25)=1 ?
The solution to ((x-6)^2)/(36)-((y+1)^2)/(25)=1 is Hyperbola with (h,k)=(6,-1),a=6,b=5