What is ((x+1)/9)^2-((y-3)/(16))^2=1 ?

The solution to ((x+1)/9)^2-((y-3)/(16))^2=1 is Hyperbola with (h,k)=(-1,3),a=9,b=16

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((x+1)/9)^2-((y-3)/(16))^2=1

(\frac{x + 1}{9})^{2} - (\frac{y - 3}{16})^{2} = 1

(h, k) = (- 1, 3), a = 9, b = 16

Solution steps

(\frac{x + 1}{9})^{2} - (\frac{y - 3}{16})^{2} = 1

Rewrite

(\frac{x + 1}{9})^{2} - (\frac{y - 3}{16})^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{9 ^{2}} - \frac{( y - 3 ) ^{2}}{1 6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 3), a = 9, b = 16

\frac{y ^{2}}{1} - \frac{x ^{2}}{9} = 1

x^{2} - y^{2} - 8 x + 10 = 0

8 x^{2} - 2 y^{2} - 12 = 0

x^{2} - y^{2} - 16 = 0

\frac{( y - 7.5 ) ^{2}}{0.25} - \frac{( x - 1 ) ^{2}}{0.25} = 1

What is ((x+1)/9)^2-((y-3)/(16))^2=1 ?
The solution to ((x+1)/9)^2-((y-3)/(16))^2=1 is Hyperbola with (h,k)=(-1,3),a=9,b=16