What is (x-8)^2-(y+6)^2=1 ?

The solution to (x-8)^2-(y+6)^2=1 is Hyperbola with (h,k)=(8,-6),a=1,b=1

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(x-8)^2-(y+6)^2=1

(x - 8)^{2} - (y + 6)^{2} = 1

(h, k) = (8, - 6), a = 1, b = 1

Solution steps

(x - 8)^{2} - (y + 6)^{2} = 1

Rewrite

(x - 8)^{2} - (y + 6)^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - 8 ) ^{2}}{1 ^{2}} - \frac{( y - ( - 6 ) ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (8, - 6), a = 1, b = 1

4 y^{2} - 2 x^{2} = 1

\frac{x ^{2}}{1} - \frac{y ^{2}}{9} = 1

\frac{( x - 6 ) ^{2}}{36} - \frac{( y + 1 ) ^{2}}{25} = 1

x, (x - 0.5)^{2} + (x + 0.5)^{2} = r (x)^{2}

25 x^{2} - 16 y^{2} = 1

What is (x-8)^2-(y+6)^2=1 ?
The solution to (x-8)^2-(y+6)^2=1 is Hyperbola with (h,k)=(8,-6),a=1,b=1