What is ((x-4)^2)/(144)-((y-11)^2)/(25)=1 ?

The solution to ((x-4)^2)/(144)-((y-11)^2)/(25)=1 is Hyperbola with (h,k)=(4,11),a=12,b=5

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((x-4)^2)/(144)-((y-11)^2)/(25)=1

\frac{( x - 4 ) ^{2}}{144} - \frac{( y - 11 ) ^{2}}{25} = 1

(h, k) = (4, 11), a = 12, b = 5

Solution steps

\frac{( x - 4 ) ^{2}}{144} - \frac{( y - 11 ) ^{2}}{25} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{144} - \frac{( y - 11 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - 4 ) ^{2}}{1 2 ^{2}} - \frac{( y - 11 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, 11), a = 12, b = 5

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

7 x^{2} - 5 y^{2} - 14 x + 40 y - 108 = 0

y^{2} - x^{2} = 25

36 (x - 5)^{2} - 64 (y - 2)^{2} = 2304

\frac{( y - 4 ) ^{2}}{36} - \frac{( x - 1 ) ^{2}}{16} = 1

What is ((x-4)^2)/(144)-((y-11)^2)/(25)=1 ?
The solution to ((x-4)^2)/(144)-((y-11)^2)/(25)=1 is Hyperbola with (h,k)=(4,11),a=12,b=5