What is ((x-2)^2)/9-((y-1)^2)/4 =1 ?

The solution to ((x-2)^2)/9-((y-1)^2)/4 =1 is Hyperbola with (h,k)=(2,1),a=3,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-2)^2)/9-((y-1)^2)/4 =1

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

(h, k) = (2, 1), a = 3, b = 2

Solution steps

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{3 ^{2}} - \frac{( y - 1 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 1), a = 3, b = 2

7 x^{2} - 5 y^{2} - 14 x + 40 y - 108 = 0

y^{2} - x^{2} = 25

36 (x - 5)^{2} - 64 (y - 2)^{2} = 2304

\frac{( y - 4 ) ^{2}}{36} - \frac{( x - 1 ) ^{2}}{16} = 1

- 16 x^{2} + y^{2} + 128 x + 2 y - 271 = 0

What is ((x-2)^2)/9-((y-1)^2)/4 =1 ?
The solution to ((x-2)^2)/9-((y-1)^2)/4 =1 is Hyperbola with (h,k)=(2,1),a=3,b=2