What is ((x-1)^2)/4-((y+2)^2)/(16)=1 ?

The solution to ((x-1)^2)/4-((y+2)^2)/(16)=1 is Hyperbola with (h,k)=(1,-2),a=2,b=4

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((x-1)^2)/4-((y+2)^2)/(16)=1

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{16} = 1

(h, k) = (1, - 2), a = 2, b = 4

Solution steps

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 2, b = 4

\frac{( x ^{(2)} )}{( 144 )} - \frac{( y ^{(2)} )}{( 81 )} = 1

9 x^{(2)} - 4 y^{(2)} + 18 x - 27 = 0

4 x^{2} - 5 y^{2} - 16 x - 30 y - 9 = 0

\frac{( x - 1.6 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{2} = 1

\frac{( x - 4 ) ^{2}}{144} - \frac{( y - 11 ) ^{2}}{25} = 1

What is ((x-1)^2)/4-((y+2)^2)/(16)=1 ?
The solution to ((x-1)^2)/4-((y+2)^2)/(16)=1 is Hyperbola with (h,k)=(1,-2),a=2,b=4