What is (y^2)/(36)-(x^2)/(64)=1 ?

The solution to (y^2)/(36)-(x^2)/(64)=1 is Hyperbola with (h,k)=(0,0),a=6,b=8

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(y^2)/(36)-(x^2)/(64)=1

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1

(h, k) = (0, 0), a = 6, b = 8

Solution steps

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1

Rewrite

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{6 ^{2}} - \frac{( x - 0 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 6, b = 8

(\frac{x + 1}{3 ^{2}})^{2} - (\frac{y - 3}{4 ^{2}})^{2} = 1

\frac{x ^{2}}{4} - \frac{y ^{2}}{36} = 1

x^{2} + 2 y + x = 2 y^{2} + 3 y + 2 x + 2

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

(x + y) (x - y) - 2 = 0

What is (y^2)/(36)-(x^2)/(64)=1 ?
The solution to (y^2)/(36)-(x^2)/(64)=1 is Hyperbola with (h,k)=(0,0),a=6,b=8