What is -4x^2+24x+16y^2-128y+156=0 ?

The solution to -4x^2+24x+16y^2-128y+156=0 is Hyperbola with (h,k)=(3,4),a=2,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-4x^2+24x+16y^2-128y+156=0

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

(h, k) = (3, 4), a = 2, b = 4

Solution steps

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

Rewrite

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{2 ^{2}} - \frac{( x - 3 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 4), a = 2, b = 4

(x + y) (x - y) - 2 = 0

\frac{y ^{2}}{a ^{2}} - \frac{x ^{2}}{b ^{2}} = 1

\frac{( y - 5 ) ^{2}}{25} - \frac{( x + 5 ) ^{2}}{9} = 1

4 x^{2} - 9 y^{2} + 4 x + 36 y - 36 = 0

9 x^{2} - 16 y^{2} - 36 x + 96 y - 252 = 0

What is -4x^2+24x+16y^2-128y+156=0 ?
The solution to -4x^2+24x+16y^2-128y+156=0 is Hyperbola with (h,k)=(3,4),a=2,b=4